2|X-Y|+√2Y+Z+Z²-Z+1/4=0求X+Y+Z的值
来源:百度知道 编辑:UC知道 时间:2024/06/30 16:39:10
y=负八分之根号二,x=负八分之根号二,z=0
x+y+z=负四分之根号二
2|X-Y|+√(2Y+Z)+Z²-Z+1/4=0
2|X-Y|+√(2Y+Z)+(Z-1/2)²=0
X-Y=0
2Y+Z=0
Z-1/2=0
所以
Z=1/2
2Y+1/2=0
Y=-1/4
X-(-1/4)=0
X=-1/4
X+Y+Z
=(-1/4)+(-1/4)+1/2
=0
根号范围是多少是2|X-Y|+√(2Y+Z)+Z²-Z+1/4=0吗?
这样可得2|X-Y|+√(2Y+Z)+(Z-1/2)²=0
三个式子都为0,即
X-Y=0
2Y+Z=0
Z-1/2=0
可得
Z=1/2 Y=-1/4 X=-1/4
所以X+Y+Z==-1/2
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